What happens when you attempt to compile and run the following code?
#include <iostream>
#include <set>
#include <vector>
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector<int>v(t, t+10);
multiset<int> s1(v.begin(),v.end());
s1.insert(v.begin(),v.end());
pair<multiset<int>::iterator,multiset<int>::iterator> range; range = s1.equal_range(6); while (range.first != range.second) { cout<<*range.first<<" "; range.first++;
}
return 0;
}
Answer : A
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out<<val<<" ";
}
};
struct Sequence {
int start;
Sequence(int start):start(start){}
int operator()() {
return start++ ; }};
int main() {
vector<int> v1(10);
generate(v1.rbegin(), v1.rend(), Sequence(1));
rotate(v1.begin(),v1.begin() + 1, v1.end() );
for_each(v1.begin(), v1.end(), Out<int>(cout) );cout<<endl; return 0;
}
Program outputs:
Answer : C
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <fstream>
#include <string>
#include <list>
#include <algorithm>
#include <iomanip>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int() const { return val; };};
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out<<setw(3)<<hex<<val; } }; int main () { int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; fstream f("test.out", ios::trunc|ios::out); list<B> l(t, t+10); for_each(l.begin(), l.end(), Out<B>(f)); f.close(); f.open("test.out"); for( ; f.good() ; ) {
B i;
f>>i;
cout<<i<<" ";
}
f.close();
return 0;
}
Answer : D
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: one two three<enter>?
#include <iostream>
#include <string>
using namespace std;
int main ()
{
string a;
cin>>a;
cout<<a<<endl;
return 0;
}
Program will output:
Answer : A
What will happen when you attempt to compile and run the following code?
#include <iostream>
#include <map>
#include <vector>
#include <sstream>
#include <string>
using namespace std;
int main() {
int t[] = { 3, 4, 2, 1, 0, 3, 4, 1, 2, 0 };
vector<int> v(t, t + 10);
multimap<int, string> m;
for (vector<int>::iterator i = v.begin(); i != v.end(); i++) { stringstream s;s << *i << *i; m.insert(pair<int, string>(*i, s.str()));
}
pair<multimap<int, string>::iterator, multimap<int, string>::iterator> range; range = m.equal_range(2); for (multimap<int, string>::iterator i = range.first; i != range.second; i++) { cout << i?>first << " ";
}
return 0;
}
The output will be:
Answer : A